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How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.00 M solution?

How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.00 M solution?

How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution? 1200 mL will be the final volume of the solution. However, since there’s already 500 mL of solution present, you only need to add 700 mL of water to get 1200 mL as your final volume. The answer: 700 mL.

What would be the molarity of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL?

The concentration would be 0.76 mol/L.

What is molarity of dilution?

Concentrations may be measured using various units, with one very useful unit being molarity, defined as the number of moles of solute per liter of solution. The solute concentration of a solution may be decreased by adding solvent, a process referred to as dilution.

How many mL of water are needed to dilute 65ml 7m HCl to 2M?

Expert-verified answer So, 162. 5 mL of water has to be added.

What is the molarity of a solution made by diluting 26.5 mL of 6.00 M HNO3 to a volume of 250 mL?

The correct answer is: 36.5g NaCl What is the molarity of a solution made by diluting 26.5 mL of 6.00M HNO3 to a volume of 250 mL? The correct answer is: 0.636M How many mL of 10.8M HCl are required to make 100.0mL of 3.00M acid?

What is the concentration of a solution containing 37.9 mL of bromine diluted to 250 mL with water?

With water we can find the concentration volume percent. That volume percent is equal to the volume of bromine divided by volume of solution, multiplied by 100. So here we substitute the Values we get 31.9 divided by 250, multiplied by 100 which is equal to 15.16, Which will be equal to by solving this 15.16.

What is molarity give example?

Molarity is the number of moles of solute per liter of solution. For example, if you dissolve table salt in water, salt is the solute, and water is the solution. One mole of sodium chloride weighs 58.44 grams. If you dissolve 58.44 grams of NaCl in one liter of water, you have a one molar solution, abbreviated as 1M.

How many ml of water must be added to 200ml of 0.65 M HCl to dilute the solution to 0.20 m?

(a) 450 mL Thus the volume of diluted solution is 650 ml. i.e., the volume of solution after adding water to initial 200 ml is 650 ml.

What volume of water would be needed to dilute 50 ml of a 3 M HCl solution to 1 M?

Therefore, you need 100 ml of water to make a final volume of 150 because 50 ml comes from the Original Volume of 3M HCl.

What is the molarity of 1.0 mol KCl in 750 ml of solution?

1 Answer. Approx. 1.3 mol⋅L−1 with respect to KCl .

How many moles of NaCl are present in a solution with a molarity of 8.50 9m and 125 ml of solution?

So this later and later can slope. So on multiplication 8.59 and 2.125 we get the value 1.07 so 1.07 mall of sodium chloride. So therefore the correct answers to the moles of sodium chloride from all of sodium chloride that is equal to 1.07 mol.

How to calculate molarity dilution?

C1 is the concentration of the stock solution.

  • V1 is the volume to be removed (i.e.,aliquoted) from the concentrated stock solution.
  • C2 is the final concentration of the diluted solution.
  • V2 is the final volume of the diluted solution.
  • An alternative and commonly-used notation for this equation is M1V1 = M2V2,where M is used in place of C.
  • How do you calculate dilution?

    – Enter 10 into the Concentration (start) box and select the correct unit (millimolar) – Enter 50 into the Concentration (final) box and select the correct unit (micromolar) – Enter 20 into the Volume (final) box and select the correct unit (milliliter) – Press calculate – The answer of 100 microliter (0.1 ml) appears in the Volume (start) box

    How to make simple solutions and dilutions?

    V 1 = Volume of stock solution needed to make the new solution

  • C 1 = Concentration of stock solution
  • V 2 = Final volume of new solution
  • C 2 = Final concentration of new solution
  • Example: Make 5 mL of a 0.25 M solution from a 1 M solution
  • Formula: C 1 V 1 = C 2 V 2
  • Plug values in: (V 1 ) (1 M) = (5 mL) (0.25 M)
  • How do you calculate molarity?

    – Molarity = moles solute/Liter solution – Molarity = 0.15 moles of KMnO 4 /0.75 L of solution – Molarity = 0.20 M