## Can we implement and gate using mux?

Multiplexer can act as universal combinational circuit. All the standard logic gates can be implemented with multiplexers. It is NOT Gate using 2:1 MUX.

### Can mux be used for implementing functions?

Let A and B are the select lines and C be the input, Thus, for the implementation of given logical function, required is one 4×1 MUX and and inverter.

**Which gate is used in mux?**

Multiplexers, or MUX’s, can be either digital circuits made from high speed logic gates used to switch digital or binary data or they can be analogue types using transistors, MOSFET’s or relays to switch one of the voltage or current inputs through to a single output.

**How do you make a NOT gate using mux?**

A 4:1 MUX has 2 select lines and 4 inputs. Let the select lines be S0,S1 and inputs be I3,I2,I1,I0. Inorder to make it work as a not gate. Short circuit the select lines S0 and S1,here it acts as input.

## What mux size do you need to implement N variable functions?

You need a 2^N input multiplexer for N inputs.

### How many gates are in a MUX?

From the above output expression, the logic circuit of 2-to-1 multiplexer can be implemented using logic gates as shown in figure. It consists of two AND gates, one NOT gate and one OR gate.

**How many and gates are required for 1 to 16 de multiplexer?**

1 to 16 demultiplexer has one input data, four select lines A, B, C and D and 16 output lines Y0 to Y15. This is implemented using AND and NOT gate. 1 to 16 demultiplexer is implemented using the logic circuit below. This can be implemented using 1 to 8 demultiplexer, 1 to 4 demultiplexer and 1 to 2 demultiplexer.

**How many and gates are required for a 128?**

Discussion :: Counters – General Questions (Q. No. 16)

[A]. | 128 gates, 6 inputs to each gate |
---|---|

[B]. | 64 gates, 5 inputs to each gate |

[C]. | 64 gates, 6 inputs to each gate |

[D]. | 128 gates, 5 inputs to each gate |

## What is the minimum number of 2 1 mux are required to implement two input AND gate?

The minimum number of 2 to 1 multiplexers are required to implement 4 to 1 Multiplexer is. We need to implement 4 to 1 Mux using 2 to 1 Mux. We need 4/2 = 2 in first level and 2/2 = 1 in second level. Hence, we need three 2 to 1Multiplexers to implement 4 to 1 Mux.

### What is the minimum number of 2 1 mux are required to implement two input and gate?

**How does a MUX gate work?**

How Does a Multiplexer Work? The multiplexer works like a multiple-input and single-output switch. The output gets connected to only one of the n data inputs at a given instant of time. Therefore, the multiplexer is ‘many into one’ and it works as the digital equivalent of an analog selector switch.

**How many AND gates are required for a 8 to 1 multiplexer?**

8 AND gates

For a 1 to 8 multiplexer a total of 8 AND gates are required.

## How many two input and and or gates are required to Realise Y is equal to CD CA ji?

Explanation: To realize Y = CD + EF + G, two AND gates are required and two OR gates are required.

### How many and gates are required for 1 8multiplexer?

**How do you implement a 4×1 mux?**

4×1 Multiplexer has four data inputs I3, I2, I1 & I0, two selection lines s1 & s0 and one output Y. The block diagram of 4×1 Multiplexer is shown in the following figure. One of these 4 inputs will be connected to the output based on the combination of inputs present at these two selection lines.