Can memset be used on int array?
Nope. memset() casts down to a byte and dupes it across the region.
Does memset work on 2D array?
If the 2D array has automatic storage duration, then you can use an array initializer list to set all members to zero. int arr[10][20] = {0}; // easier way // this does the same memset(arr, 0, sizeof arr); If you allocate your array dynamically, then you can use memset to set all bytes to zero.
How memset is implemented?
We can easily implement the memset() function in C programming. You need to typecast the given buffer memory to unsigned char*. After that typecasting the value with unsigned char, assigned the value to each byte of the buffer until n (given length).
Is calloc faster than memset?
If you end up using the memory anyway, calloc() is still faster than malloc() and memset() but the difference is not quite so ridiculous.
Is it possible to Memset an array of integers?
int arr [15]; int i; for (i=0; i<6; ++i) // Set the first 6 elements in the array arr [i] = 1; // to the value 1. Short answer, NO. Long answer, memset sets bytes and works for characters because they are single bytes, but integers are not.
How does Memset work byte by byte?
Now, memset () works byte by byte, and one byte representation ( unsigned char) of 0 is 00000000. So, it becomes- Therefore, both a [0] and a [1] are initialized with 0. Now, lets see memset (a, -1, sizeof (a)): one byte for -1 is 11111111.
Is it possible to use Memset to fill a memory region?
No, you can’t [portably] use memset for that purpose, unless the desired target value is 0. memset treats the target memory region as an array of bytes, not an array of int s. A fairly popular hack for filling a memory region with a repetitive pattern is actually based on memcpy.
What is the value of 0 in Memset?
When all bits of a number are 0, its value is also 0. However, if all bits are 1 the value is -1. Then, we write memset (a, 0, sizeof (a)). Now, memset () works byte by byte, and one byte representation ( unsigned char) of 0 is 00000000.